AthenaHealth Fresher Interview Questions with answers .

This blog briefly explains about AthenaHealth Fresher Interview Questions with answers . Some of the questions are :

1 . Buy 6 Get 1 Discount

What is the discount shop keeper gives on buy 6 get 1?

ANSWER :

   If the price of each article = Rs. 10

   Then at  the cost of Rs. 60 the shop keeper will give 7 articles.

    So the customer will get ( 60 / 7 ) discount =   8.57 %

 

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2. Question on Time and Work

D can complete the work in 10 days. A alone can do a piece of work in 15 days and B alone in 20 days. How many days will take for A and B to complete the work, as working together. And the payment for that work is Rs.9000. What will be the share for A and B?

SOLUTION :

        A’s one day work               =   1 / 15

        B’s one day work               =  1 /  20 

        ( A + B )’ s one day work   =    1 / 15   +  1 / 20

                                                           =   ( 3 + 4 ) /  60       =   7 / 60

   Hence A and B together finish the work in  60 / 7 days =  8.57 days

       Share of A    =  ( 60 / 7 ) * ( 1 / 15 )  of Rs. 9000

                               =  ( 4 / 7 ) *  9000    =  Rs.  5143

       Share of B     =   ( 3 / 7 ) *  9000   =  Rs.  3857

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3. There are 25 Horses which all run at different speeds. A faster horse always beats a slower horse. You can race 5 horses at a time. There are no ties and you may not time them. What is the minimum number of races needed to determine the 3 fastest horses in order from fastest to slowest?

ANSWER :  7 races

REASON : In the first five races having 5 horses in each race we get five  horses   running fast . Having two more races among the five horses we get 3 fastest horses  in order from fastest to the slowest.

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4.  In a class if 1 is absent the rest of them can be divided into 6 equal groups and if two are absent can be divided into 7 equal groups. Find the minimum number of students in the class?

  ANSWER :  37 students

   REASON :   37 =  37 –  1  =  36   = 6 (6)

                          37 =  37 – 2   =  35   = 7 (5)

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5. A person sees the mirror image of the clock at home and travels 20 Minutes to a camp. He notices that he is 2 hour and 30 minutes late. What is the time at the home when he started?

   ANSWER :

First subtract 20 minutes from 2 1/2 hours to compensate for his 20 minute bike ride to give a difference of 2 hours and 10 minutes.

So, divide that 2 hours and 10 minutes by 2 and this will give you the center-point (65 minutes) for compensating for the mirror. 

By adding that 65 minutes to 6 o’clock you get the time he left home (7:05), and the time he saw in the mirror (4:55). 

Furthermore, by re-adding the 20 minutes from when he left (7:05), you get what time he got to camp (7:25).

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