TRICKY MATHS PUZZLES –  WITH ANSWERS – PART – II

Here in this blog we are discussing about TRICKY MATHS PUZZLES –  WITH ANSWERS – PART – II . Some of them are illustrated below :

                We have already discussed about some problems in the previous blog TRICKY MATHS PUZZLES – PART – I . 

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  1.   SOLVE THE GIVEN TRICKY QUESTION .

GIVEN : The cost of three red balloons = Rs. 21 

                The  cost of one red and two pairs of blue balloons = Rs. 31

                 The cost of one pair of blue balloons and two orange balloons = Rs. 20 

                                  

                          red 1    +       red 1       +   red 1                   =   21

                          red 1   +       blue 2       +       blue 2                  =    31

                      blue 2        +   orange   +   orange           =   20

red 1       +       blue 2           x    orange    =   ?

 

                  red 1   +       red 1      +      red 1     =  21 

 Three red balloons = Rs. 21  

                 3         red 1       =   21 

Then the cost of one red balloon = Rs. 7

                   

                     =>         red 1  =  7

   

            red 1    +             blue 2    +     blue 2          =  31

      Again the cost of one red and two pairs of blue balloons = Rs. 31 

Also the cost of one red balloon = Rs. 7 

So the cost of two pairs of blue balloons = 31 – 7

        7      +        blue 2          +         blue 2     =  31

      2        blue 2    = 31 – 7

              blue 2      = 24                         blue 2     = 12

 Thus the cost of one pair of blue balloon = Rs. 12 

 

We already knew that the cost of one pair of blue balloons  is Rs. 12 

 Here the cost of one pair blue and two orange balloons = Rs. 20 

 

             blue 2     +         orange       +       orange        =   20

           12    +           orange    +     orange         =   20

 Hence the cost of two orange balloons =  Rs . 20 – Rs . 12

                                                                              =  Rs. 8

     2       orange        =  20 – 12   =   8 

              orange        =  4

 

                So the cost of orange balloon = Rs.4        

                       red 1   +            blue 2        x                orange  =   ?

 Coming to the given question , what is the cost of above ? 

Cost of red balloon                = Rs. 7 

Cost of pair of blue  balloon = Rs. 12 

Cost of orange balloon         = Rs. 4

               

                  7      +        12      x        4         =   ?

  

                  7      +      (  12    x   4   )          =   ?

                                            7    +    48      =  55  

 Thus the cost of the given balloons = Rs. 55

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  REFERENCES : https://youtu.be/PIMaHCt2wL0

 For further details visit the page given below :

 ( TRICKY MATHS PUZZLES – PART – I )

   https://payilagam.com/blogs/tricky-maths-puzzles-part-i/

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  COURTESY : https://www.youtube.com/results?search_query=maths+tricky+puzzles

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