Here in this blog, we are discussing SEDIN – Fresher Interview Questions – Part II in Quantitative Aptitude. They are :
1. What is the least number that must be added to 1056, so that the number is completely divisible by 23?
SOLUTION :
On dividing 1056 by 23, we get 45 as the quotient and 21 as the remainder. So it is sufficient to add the number 2 to 1056
- 2 + 1056 = 1058, exactly divisible by 23.
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2. The sum of the ages of 5 children born at intervals of 3 years each is 50 years. What is the age of the youngest child?
SOLUTION :
Let the age of the five children be x , ( x + 3 ) , (x + 6 ) , (x + 9) and (x + 12) respectively.
Sum of their ages = 50 years. Then,
x + ( x+ 3 ) + ( x +6 ) + ( x+ 9 ) + ( x+12 ) = 50
5x + 30 = 50 => 5x = 20
=> x = 4 years.
Thus, the age of the youngest child is 4 years.
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3.The cost price of 20 mangoes is same as the selling price of X mangoes. If the profit is 25% then the value of X is ?
SOLUTION :
Let the cost price of 20 mangoes = Rs. 20
- Cost price of each mango = Rs. 1
If the profit is 25 % then the profit = Rs. 20 * 25 / 100 = Rs. 5
then the Selling price of 20 mangoes = Rs. 25
- Thus the Selling price of one mango = 25 /20 = Rs. 1.25
Value of x = 20 / 1.25 = 16
Hence , 16 mangoes are sold at the cost price of 20 mangoes.
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4.On 8th December 2007 Saturday falls. What day of the week was it on 8th December 2006 ?
SOLUTION :
The year 2007 is an ordinary year so the day 8th December 2007 will be the next odd day for the the day on 8th December 2006.
- The day 8th December 2006 will be Friday .
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