Aspire Systems Interview Questions with Answers

Aspire Systems Interview Questions with Answers – Part 1

This blog explains about Aspire Systems Interview Questions with Answers – Part 1 and is given below :

ASPIRE SYSTEMS – Written Test Part A – APTITUDE QUESTIONS

1. Which number replaces the question marks ?

734619
110907
524232
995001
678297
1548??

Answer	:	8,1
Explanation	:	Reading each row as 3 separate 2-digit numbers, the central number equals the average of the left and right hand numbers.

2. Which letter replaces the question mark?

A. Y B. X C. Z D. A

Answer : Option A

Correct Answer : Y

Here, start with the top point of each star, and move clockwise around the other points. Letters advance through the alphabet in steps of 5 for the left hand star, 6 for the central star, and 7 for the right hand star.

3. Fact 1. Mary said, “Ann and I both have cats

Fact 2: Ann said, “I don’t have a cat”

Fact 3: Mary always tells the truth, but Ann sometimes lies

If the following three statements are facts , which of the following statements must also be a fact?

I: Ann has a cat

II: Mary has a cat

III : Ann is lying

I only
II only
I and II only
All the statements are facts.

Answer : Option D

Explanation :

If Mary always tells the truth, then both Ann and Mary have cats (statements I and II), and Ann is lying (statement III). So all the statements are facts.

4. Out of. 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

A. 210 B. 1050 C. 25200 D. 21400

Answer : Option C

Explanation :

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

= (⁷C₃ x ⁴C₂)

=		7 x 6 x 5	x	4 x 3
		3 x 2 x 1		2 x 1

= 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

Number of ways of arranging 5 letters among themselves	= 5!
	= 5 x 4 x 3 x 2 x 1
	= 120.

Required number of ways = (210 x 120) = 25200.

5. If log _x (9/16) = -1/2 , then x is equal to:

A -3/4

B. 3/4

C.81/256

D.256/81

Answer : Option B

Explanation :

Log x(9/16) = -1/2

Log x (9/16 ) = log (3/4) = x logx(-1/2)

Hence the value of X = 3/4

6. In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will boat B by:

A. 22. 75 m

B .25 m

C 19. 5 m

D. 7(4/7) m

Answer : Option B

Explanation :

A : B = 200 : 169.

A : C = 200 : 182.

182

200

= 182 : 169.

200

169

When C covers 182 m, B covers 169 m.

When C covers 350 m, B covers		169	x 350	m	= 325 m.
		182

Therefore, C beats B by (350 – 325) m = 25 m.

7. A car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs . 4000 each year?

A. Rs. 7.98 B. 8.50 C.Rs. 8 D. Rs. 9

Answer : Option A

Explanation :

Total quantity of petrol
consumed in 3 years

=		4000	+	4000	+	4000		litres
		7.50		8		8.50

= 4000		2	+	1	+	2		litres
		15		8		17

=		76700		litres
		51

Total amount spent = Rs. (3 x 4000) = Rs. 12000.

Average cost = Rs.		12000 x 51		= Rs.	6120	= Rs. 7.98
		76700			767

8. Reena took a loan of Rs 1200 with simple interest for as many years as the rate of Interest . If she paid Re. 432 as interest at the end of the loan period , what was the rate of Interest?

A. 3.6

B. 6

C. 6.3

D. 3.3

Answer : Option B

Explanation :

Let rate = R% and time = R years.

Then,		1200 x R x R		= 432
		100

12R² = 432

R² = 36

R = 6.

9. X can do a piece of work at 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they work together to complete the work? A. 13 1/3 days B. 15 days C. 25 days D. 26 days

Answer : Option A

Explanation :

Work done by X in 8 days =		1	x 8		=	1	.
		40				5

Remaining work =		1 –	1		=	4	.
			5			5

Now,	4	work is done by Y in 16 days.
	5

Whole work will be done by Y in		16 x	5		= 20 days.
			4

X’s 1 day’s work =	1	, Y’s 1 day’s work =	1	.
	40		20

(X + Y)’s 1 day’s work =		1	+	1		=	3	.
		40		20			40

Hence, X and Y will together complete the work in		40		= 13	1	days.
		3			3

10. The salaries A, B, C are in the ratio 2 : 3 : 5 If the increments of 15 %,10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

A. 3: 3 : 10

B. 10 : 11 : 20

C. 23 : 33 : 60

D. Can’t be determined

Answer : option C

Explanation :

Let A = 2k, B = 3k and C = 5k.

A’s new salary =	115	of 2k =		115	x 2k		=	23k
	100			100				10

B’s new salary =	110	of 3k =		110	x 3k		=	33k
	100			100				10

C’s new salary =	120	of 5k =		120	x 5k		= 6k
	100			100

New ratio		23k	:	33k	: 6k		= 23 : 33 : 60
		10		10

11. INDIGENT : WEALTHY , Select the similar one

A. angry : rich

B. native : Affluent

C. gauche : graceful

D. Scholarly : erudite

Answer : option C

Correct Answer : Y

12. DEF , DEF2 , DE2F2 , ____ , D2E2F3

A. DEF2

B. D2EF2

C. D2E2F

D. D2E2F2

Answer : Option D

Explanation :

In this series, the letters remain the same: DEF.

The subscript numbers follow this series:

111, 112, 122, 222, 223, 233, 333, …

13. On what dates of April , 2001 did Wednesday fall ?

A. 1, 8 , 15 , 22, 29

B. 2 , 9 ,16 , 23, 30

C. 3, 10 , 17 , 24

D. 4 , 11 , 18 , 25

Answer : Option D

Explanation :

We shall find the day on 1^st April, 2001.

1^st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.

Total number of odd days = (0 + 0 + 0) = 0

On 1^st April, 2001 it was Sunday.

In April, 2001 Wednesday falls on 4^th, 11^th, 18^th and 25^th.

14. The interest on Rs. 750 for 2 years is the same as the true discount of Rs. 960 due 2 years hence. If the rate of interest is the same in both cases , it is

A. 12 % B. 15 % C. 14 % D. 16 (2/3) %

Answer : Option C

Explanation :

S.I. on Rs. 750 = T.D. on Rs. 960.

This means P.W. of Rs. 960 due 2 years hence is Rs. 750.

T.D. = Rs. (960 – 750) = Rs. 210.

Thus, S.I. on R.s 750 for 2 years is Rs. 210.