Here in this blog we are discussing about ADF – Interview Aptitude Questions – Payilagam – Part – V . Some of them are :

1. The profit earned by selling an article for Rs. 832 equal to the loss incurred when            the same article is sold for Rs. 448 .  What should be the sale price for making a         profit of 50%  ?

a) 920      b) 960          c) 1060      d) 1200

SOLUTION :

Let the cost price of that article be Rs. X then the

Selling price – Cost price =   Cost price – Loss

•                            832   –   x       =        x   –   448
•                                      =>   2x  =        832 + 448            =  Rs.1280
•                        X = cost price = Rs.640
•                      Now the profit = 50% 0f Rs. 640 = 320
•   Thus the new cost price = Rs. 640 + 320 = Rs.960

———————————————————————

2.A train of 108 m long moving at the speed of 50 kmph crosses a train 112 m long  coming from the opposite direction in 6 seconds. The speed of the second train is ?

a)48 kmph                 b)54 kmph                       c)66 kmph                  d)82 kmph

SOLUTION:

Total distance = 108 + 112 m =  220 m

Speed of the first train = 50 kmph and the second train = x kmph

Relative speed = x + 50 kmph = (x + 50) * 5 / 18   m/sec

Total time taken = 6 seconds

(X + 50 ) 5 /18   =   220 / 6

(X + 50 ) 5 = 3 * 220

X +  50 =      132  =>    x = 82 kmph

Speed of the second train = 82 kmph

—————————————–

3 . In an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks are

a) 500 b)        550                 c)       640                d) 1008

SOLUTION :

From the given data we get the maximum marks to pass =  113 + 85 = 198 marks

36 % of X marks = 198 marks

100 % of X marks = (198 / 36 )   * 100

=  11 *50 =  550 marks

———————————————
4. If the diameter of the cylindrical jar is increased by 25 % by what percent must the height be decreased so that the volume remains unaltered ?

a) 10                   b) 20                 c) 25               d) 36

SOLUTION :

Let the diameter of a cylinder =  8 cm    => radius = r1 = 4 cm

Increase in 25 % of diameter = 8cm + 2 cm = 10 cm

=> New radius =   r2 = 5 cm

If the height of the cylinder = h cm

Volume = π r12h1 = π r22 h2

16 h1 = 25 h2

Change in height =  h –  (16 / 25)  h   = 9 /25 h

Percentage in change in height =( 9 /25 )  * 100    = 9 * 4

=   36 %

———————————————————————–

5.The number of ordered pairs of intergers ( m,n) such that the product ‘mn’ is non negative and m3 + n3 + 99 mn = 333

a) 30 b)    32                      c)   33                         d) 34

ANSWER :  33 because the product ( 99 )is a multiple of 33

——————————————

6. A father is 30 years older than his son however he will be only thrice as old as the son after 5 years, what is the father’s present age ?

a) 40 years b) 30 years                       c) 50 years           d) None of these

SOLUTION :

Let the son’s present age =   x years

Then the father’s present age =   ( x + 30) years

After 5 years ,  Son’s age =    x  + 5    and father’s age =  x + 35

Given ,     ( x  +  35 ) =  3 ( x  + 5 )

•                                       X + 35 = 3 X + 15
•                                              2X =   20 years      =>     x = 10 years.
•
•       Thus the father’s present age = 40 years

—————————————————–