Here in this blog we are discussing about ADF – Interview Aptitude Questions – Payilagam – Part – V . Some of them are :
1. The profit earned by selling an article for Rs. 832 equal to the loss incurred when the same article is sold for Rs. 448 . What should be the sale price for making a profit of 50% ?
a) 920 b) 960 c) 1060 d) 1200
SOLUTION :
Let the cost price of that article be Rs. X then the
Selling price – Cost price = Cost price – Loss
- 832 – x = x – 448
- => 2x = 832 + 448 = Rs.1280
- X = cost price = Rs.640
- Now the profit = 50% 0f Rs. 640 = 320
- Thus the new cost price = Rs. 640 + 320 = Rs.960
———————————————————————
2.A train of 108 m long moving at the speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is ?
a)48 kmph b)54 kmph c)66 kmph d)82 kmph
SOLUTION:
Total distance = 108 + 112 m = 220 m
Speed of the first train = 50 kmph and the second train = x kmph
Relative speed = x + 50 kmph = (x + 50) * 5 / 18 m/sec
Total time taken = 6 seconds
(X + 50 ) 5 /18 = 220 / 6
(X + 50 ) 5 = 3 * 220
X + 50 = 132 => x = 82 kmph
Speed of the second train = 82 kmph
—————————————–
3 . In an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks are
a) 500 b) 550 c) 640 d) 1008
SOLUTION :
From the given data we get the maximum marks to pass = 113 + 85 = 198 marks
36 % of X marks = 198 marks
100 % of X marks = (198 / 36 ) * 100
= 11 *50 = 550 marks
———————————————
4. If the diameter of the cylindrical jar is increased by 25 % by what percent must the height be decreased so that the volume remains unaltered ?
a) 10 b) 20 c) 25 d) 36
SOLUTION :
Let the diameter of a cylinder = 8 cm => radius = r1 = 4 cm
Increase in 25 % of diameter = 8cm + 2 cm = 10 cm
=> New radius = r2 = 5 cm
If the height of the cylinder = h cm
Volume = π r12h1 = π r22 h2
16 h1 = 25 h2
Change in height = h – (16 / 25) h = 9 /25 h
Percentage in change in height =( 9 /25 ) * 100 = 9 * 4
= 36 %
———————————————————————–
5.The number of ordered pairs of intergers ( m,n) such that the product ‘mn’ is non negative and m3 + n3 + 99 mn = 333
a) 30 b) 32 c) 33 d) 34
ANSWER : 33 because the product ( 99 )is a multiple of 33
——————————————
6. A father is 30 years older than his son however he will be only thrice as old as the son after 5 years, what is the father’s present age ?
a) 40 years b) 30 years c) 50 years d) None of these
SOLUTION :
Let the son’s present age = x years
Then the father’s present age = ( x + 30) years
After 5 years , Son’s age = x + 5 and father’s age = x + 35
Given , ( x + 35 ) = 3 ( x + 5 )
- X + 35 = 3 X + 15
- 2X = 20 years => x = 10 years.
- Thus the father’s present age = 40 years
—————————————————–