## Learn Programming through Logical Thinking – Series – 4

### This blog explains about Learn Programming through Logical Thinking – Series – 4 and is below :

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This is Learn Programming through Logical Thinking Series – 4.  In this series, we are converting the logical problems into Java Programs.  We are discussing about “Rearranging letters in a given word” problem in this blog post.

## Rearranging Letters Problem with Answer in Java

### Algorithm:

Step 1: Get the word “leading” from the user.

Step 2: Separate the “vowels” and “consonants”.

Step 3: Identify the vowels (“eai”) and consonants (“ldng”).

Step 4: Vowels are always together.  Thus they can be formed as one letter.  So their value is ‘1’ Consonant values cannot be combined and Hence their value is ‘4’.

Step 5: Now add combined and non combined values(4+1=5).  Thus the chance will become 5!=5*4*3*2*1.

Step 6: At the same time, within vowels also we have chances of 3!=3*2*1.

Step 7: We can conclude now as number of chances is 5!*3!=720.

### Learn Programming through Logical Thinking Series – 4: Rearranging Letters Problem with Answer in Java

package com.thilack;

public static void main(String[] args) {

//String a = “LEADING”; Given String

int i;

int num=1,num1=1,temp;

int vowels=3;

//int consonant=4;

for(i=1;i<=consonants;i++)

{

num=num*i;

}

System.out.println(“Factorial of 5! is: “+num);

for(i=1;i<=vowels; i++)

{

num1=num1*i;

}

System.out.println(“Factorial of 3! is: “+num1);

temp=num*num1;

System.out.println(“Multiply 5!&3! chances are: “+temp);

}

}

OUTPUT:

Factorial of 5! is: 120

Factorial of 3! is: 6

Multiply 5!&3! chances are: 720

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