Addition of Consecutive Digits in a given Number Program

In this blog we are going to discuss about Addition of Consecutive Digits in a given Number Program . They are illustrated very well below :

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Hi,

In this post, we are going to discuss Addition of Consecutive Digits in a given Number program.

Add numbers by below Method

We can take n numbers, For Example

We can take 5, for this, we should take 1-5. Now, we need to add the consecutive digits in the given number 5.

(1+2)+(2+3)+(3+4)+(4+5) = 24

Addition of Consecutive Digits in a given Number – Program:

public class Program {

public static void main(String[] args) {

int result=0,i,a=0;

System.out.print(“Enter the number of n value”+” “);

int num;

Scanner scan = new Scanner(System.in);

num = scan.nextInt();

for(i=1;i<num;i++){

int n=i;

a= n+(++n);

result=result+a;

}

System.out.println(“Total of n number is”+” ” +result);

}

Also there is a java run program given below :

// Java program to print a consecutive sequence 
// to express N if possible. 
class GfG 
{ 
    // Print consecutive numbers from 
    // last to first 
    static void printConsecutive(int last, int first) 
    { 
        System.out.print(first++); 
        for (int x = first; x<= last; x++) 
            System.out.print(" + "+x); 
    }   
      
    static void findConsecutive(int N) 
    { 
        for (int last=1; last<N; last++) 
        { 
            for (int first=0; first<last; first++) 
            { 
                if (2*N == (last-first)*(last+first+1)) 
                { 
                    System.out.printf(N + " = "); 
                    printConsecutive(last, first+1); 
                    return; 
                } 
            } 
        } 
        System.out.print("-1"); 
    } 
      
    // main function 
    public static void main (String[] args)  
    { 
        int n = 12; 
        findConsecutive(n); 
    } 
} 